Optimal. Leaf size=192 \[ \frac{8 \sqrt{\pi } e^{-\frac{a}{b n}} (d+e x) \left (c (d+e x)^n\right )^{-1/n} \text{Erfi}\left (\frac{\sqrt{a+b \log \left (c (d+e x)^n\right )}}{\sqrt{b} \sqrt{n}}\right )}{15 b^{7/2} e n^{7/2}}-\frac{8 (d+e x)}{15 b^3 e n^3 \sqrt{a+b \log \left (c (d+e x)^n\right )}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}} \]
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Rubi [A] time = 0.148631, antiderivative size = 192, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.278, Rules used = {2389, 2297, 2300, 2180, 2204} \[ \frac{8 \sqrt{\pi } e^{-\frac{a}{b n}} (d+e x) \left (c (d+e x)^n\right )^{-1/n} \text{Erfi}\left (\frac{\sqrt{a+b \log \left (c (d+e x)^n\right )}}{\sqrt{b} \sqrt{n}}\right )}{15 b^{7/2} e n^{7/2}}-\frac{8 (d+e x)}{15 b^3 e n^3 \sqrt{a+b \log \left (c (d+e x)^n\right )}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}} \]
Antiderivative was successfully verified.
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Rule 2389
Rule 2297
Rule 2300
Rule 2180
Rule 2204
Rubi steps
\begin{align*} \int \frac{1}{\left (a+b \log \left (c (d+e x)^n\right )\right )^{7/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c x^n\right )\right )^{7/2}} \, dx,x,d+e x\right )}{e}\\ &=-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}}+\frac{2 \operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c x^n\right )\right )^{5/2}} \, dx,x,d+e x\right )}{5 b e n}\\ &=-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}+\frac{4 \operatorname{Subst}\left (\int \frac{1}{\left (a+b \log \left (c x^n\right )\right )^{3/2}} \, dx,x,d+e x\right )}{15 b^2 e n^2}\\ &=-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}-\frac{8 (d+e x)}{15 b^3 e n^3 \sqrt{a+b \log \left (c (d+e x)^n\right )}}+\frac{8 \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b \log \left (c x^n\right )}} \, dx,x,d+e x\right )}{15 b^3 e n^3}\\ &=-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}-\frac{8 (d+e x)}{15 b^3 e n^3 \sqrt{a+b \log \left (c (d+e x)^n\right )}}+\frac{\left (8 (d+e x) \left (c (d+e x)^n\right )^{-1/n}\right ) \operatorname{Subst}\left (\int \frac{e^{\frac{x}{n}}}{\sqrt{a+b x}} \, dx,x,\log \left (c (d+e x)^n\right )\right )}{15 b^3 e n^4}\\ &=-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}-\frac{8 (d+e x)}{15 b^3 e n^3 \sqrt{a+b \log \left (c (d+e x)^n\right )}}+\frac{\left (16 (d+e x) \left (c (d+e x)^n\right )^{-1/n}\right ) \operatorname{Subst}\left (\int e^{-\frac{a}{b n}+\frac{x^2}{b n}} \, dx,x,\sqrt{a+b \log \left (c (d+e x)^n\right )}\right )}{15 b^4 e n^4}\\ &=\frac{8 e^{-\frac{a}{b n}} \sqrt{\pi } (d+e x) \left (c (d+e x)^n\right )^{-1/n} \text{erfi}\left (\frac{\sqrt{a+b \log \left (c (d+e x)^n\right )}}{\sqrt{b} \sqrt{n}}\right )}{15 b^{7/2} e n^{7/2}}-\frac{2 (d+e x)}{5 b e n \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}}-\frac{4 (d+e x)}{15 b^2 e n^2 \left (a+b \log \left (c (d+e x)^n\right )\right )^{3/2}}-\frac{8 (d+e x)}{15 b^3 e n^3 \sqrt{a+b \log \left (c (d+e x)^n\right )}}\\ \end{align*}
Mathematica [A] time = 0.216294, size = 203, normalized size = 1.06 \[ -\frac{2 e^{-\frac{a}{b n}} (d+e x) \left (c (d+e x)^n\right )^{-1/n} \left (e^{\frac{a}{b n}} \left (c (d+e x)^n\right )^{\frac{1}{n}} \left (4 a^2+2 b (4 a+b n) \log \left (c (d+e x)^n\right )+2 a b n+4 b^2 \log ^2\left (c (d+e x)^n\right )+3 b^2 n^2\right )-4 b^2 n^2 \left (-\frac{a+b \log \left (c (d+e x)^n\right )}{b n}\right )^{5/2} \text{Gamma}\left (\frac{1}{2},-\frac{a+b \log \left (c (d+e x)^n\right )}{b n}\right )\right )}{15 b^3 e n^3 \left (a+b \log \left (c (d+e x)^n\right )\right )^{5/2}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.453, size = 0, normalized size = 0. \begin{align*} \int \left ( a+b\ln \left ( c \left ( ex+d \right ) ^{n} \right ) \right ) ^{-{\frac{7}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b \log \left ({\left (e x + d\right )}^{n} c\right ) + a\right )}^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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